Number the balls from 1 to 9. Weigh {1,2,3} against {4,5,6}. If one set is heavier, the heavier ball is among those three balls. If they're of equal weight, then the heavier ball is among {7,8,9}.
To find the heavier ball among, say, {1,2,3} only weighing once, we weigh {1} against {2}. If either one is heavier than the other, that one is the heavier ball. If they're of equal weight, {3} is the heavier ball.
For these problems, it helps to reason backwards. Start at the end: from how many balls can I discern the heavier one if I can weigh only once? Then extend to weighing twice, and so on.
Come on u can do better!!!
To find the heavier ball among, say, {1,2,3} only weighing once, we weigh {1} against {2}. If either one is heavier than the other, that one is the heavier ball. If they're of equal weight, {3} is the heavier ball.
If either one is hevier than the other... (you dont know obviously here if one is heavier or the other one is lighter)
So you are very very wrong, but keep trying!
Downvoting a post can decrease pending rewards and make it less visible. Common reasons:
Submit
Sorry I took the wrong one, you were right that one was very easy because it says one ball is havier. I change the game now for the dificult one. That is not that easy :)
Downvoting a post can decrease pending rewards and make it less visible. Common reasons:
Submit