RE: An honest view on Democracy

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An honest view on Democracy

in anarchy •  5 years ago 

I was called to perform a provably fair random drawing for @reversed-bidbot!

There are a 1098 tickets participating in this round.
@inversionistam holds tickets number 0 - 7
@ezravandi holds tickets number 8 - 11
@freebornsociety holds tickets number 12 - 29
@anjana77 holds tickets number 30 - 31
@luegenbaron holds tickets number 32 - 64
@frdem3dot0 holds tickets number 65 - 95
@reversed-bidbot holds tickets number 96 - 100
@steem-raffle holds tickets number 101 - 122
@curatorbot holds tickets number 123 - 123
@builderofcastles holds tickets number 124 - 137
@informationwar holds tickets number 138 - 280
@hamismsf holds tickets number 281 - 306
@truthforce holds tickets number 307 - 369
@tftproject holds tickets number 370 - 370
@memeboi holds tickets number 371 - 373
@goldgoatsnguns holds tickets number 374 - 374
@empress-eremmy holds tickets number 375 - 382
@natepower holds tickets number 383 - 385
@risemultiversity holds tickets number 386 - 388
@flordiaman holds tickets number 389 - 391
@thevillan holds tickets number 392 - 392
@chieppa1 holds tickets number 393 - 398
@iw-curator holds tickets number 399 - 411
@firstamendment holds tickets number 412 - 425
@amnlive holds tickets number 426 - 437
@ausbitbank holds tickets number 438 - 852
@zoidsoft holds tickets number 853 - 953
@reversehitler88 holds tickets number 954 - 955
@wakeupnd holds tickets number 956 - 1013
@evernoticethat holds tickets number 1014 - 1016
@ura-soul holds tickets number 1017 - 1059
@commonlaw holds tickets number 1060 - 1065
@aconsciousness holds tickets number 1066 - 1068
@zanoni holds tickets number 1069 - 1077
@wonderlamp holds tickets number 1078 - 1078
@clownworld holds tickets number 1079 - 1080
@jimbobbill holds tickets number 1081 - 1091
@rufusfirefly holds tickets number 1092 - 1097
The merkle root of the block in which this post will appear determines the winner.

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The block in which the above post is included has a merkle root of 567c67a121c9d0e683661d73ac69e20f1792d2ca.
To find the winner we:

  1. Convert the merkle root into base 10:
    567c67a121c9d0e683661d73ac69e20f1792d2ca = 493747526091292454463906670211425548892690895562.
  2. Compute the residual after dividing by the number of tickets: 493747526091292454463906670211425548892690895562 mod 1098 = 612.
  3. This is the winning ticket, held by @ausbitbank.

Congratulations!