I think it should be 12 combination 3
RE: Brainsteem Mathematics Challenges: Factoring Seconds
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Brainsteem Mathematics Challenges: Factoring Seconds
Brainsteem Mathematics Challenges: Factoring Seconds
I think it should be 12 combination 3
I thought that at first but I think it only works if all the items are indistinguishable, which they're not. You have to consider the fact that grouping something (x x y) (y y x) is slightly different from (y y y) (x x x) even though they both contain 3 items each.
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