Can anyone solve this puzzle???
Please comment your answer with explanation and upvote as well!
Can anyone solve this puzzle???
8 years ago by digitaldollar (49)
$0.19
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19 votes
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I get 67 .
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I second it.
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Pls explain how did u get this answer?
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It is one relatively simple interpretation without considering the finer details.
Hexagon=15
Bunch bananas = 4 (didn't count each banana separate)
Clock=3 (ignoring time)
Hence 4+3+4x15=7+60.
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Same mistake I made. The symbols are different.
Four bananas = 4
Three bananas = 3
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This is a logical puzzle rather than a mathematical problem since there is not enough given information to solve it. Here is how you solve it.
From 1st the hexagon shape has value 15.
The shape has 15 edges(6 of hexagon,5 of Pentagon and 4 of Square)
From 2nd we get value of one bunch of bananas is 4.
So each banana has value of 1.
From 3rd we get that each clock has value of 3.
Which resembles the time on the clock which is 3.
Hence by using these insights, we get the last required values as
Clock = 2 (2 in the clock)
Bananas = 3 (3 bananas in the bunch)
Hexagon = 11 (Hexagon[6 sides] and pentagon[5 sides], so 6+5=11)
So required value is
2+3+3x11=?
2+3+33=? (Multiply first - Bodmas rule)
5+33=38 and hence the answer is 38.
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Well explained! 38 is the correct answer!
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Ooops. Didn't see that the symbols in the last row are all different :D
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??
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38
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2 minutes, 2x3 bananas and 11 corners. = 19 // edit: saw its wrong lol, didn't see the multiply sign. Now it's correct. 38
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2+3+3*11= 38
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Great! 38 is the correct answer :)
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hexa = 6, penta = 5, square=4
bananas= 4
3rd row clocks: 3
last row (clock is 2, bananas3 ,hexagon and pentagon is 11)
2 + 3 + 3 x 11 = 38 is the answer.
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19 betul?
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Banana 6
Clock 2
pentagon and hexagon 11
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Nope.. try again..
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I get 67 as well.
15x3=45
4+4+15=23
4+3+3=10
(3+4)+(4x15)=67
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165
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Pls explain how did u get this answer?
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My answer is wrong. I just scanned the problem and didn't think to count bananas as individual or clock as hours.
I counted the gray shape as 15, bananas a 4 and clock as 3.
So I should have said 38
Served me right for making assumptions.
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22
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There're infinite number of solutions for this equation system.
There're 5 unknowns and only 4 equations.
Last hexagon,pentagon is different then the first hexagon,pentagon and square.
You can't find just one answer, so all answers are correct.
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Well spotted. I didn't notice that.
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