solution set of {(x,y)|y=x2} {(x,y)|y=x+2} is
A. {(-1,1),(2,4)} B.{(-1,0),(2,0)} C.{(1,-1),(4,2)} D.{(0,-1),(0,2)} E. None of these
- If a2+b2=4 and (a-b)2=2, what is the value of ab?
A. 1 B.√2 C. 2 D. 3 E.4
28.If x2-2x-15=(x+r)(r+s) for all value of x, one possible value for r-s is
A.8 B. 2 C.-2 D. -3 E. -5 - If ax2-bx-c=0, then x=………..
A. (-b±√(b^2+4ac))/2a B. (-b±√(b^2-4ac))/2a C. (b±√(b^2-4ac))/2a D.(b±√(b^2+4ac))/2a E. None of these - The parabola y=x2-x-12 cuts the X-axis at A and B. The distance between A and B is
A. 1 B. -1 C. 7 D. -7 E.12
……………………………………………………………………………………………………..Thank you!
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