Today I will announce a contest. Today's contest is different from the others. Today's contest is about circuit solving related.This is the 2nd edition of my contest .There are many people in our community who study in electrical related subjects. I did not give any difficult circuit. I have given a very simple circuit so that everyone can find out its total current . The nature of the electrical conductor for which the current flowing through it is interrupted or interrupted is called resistance and Current is the flow of electric charge . Anyway, I hope everyone like the contest and everyone will participate.
The question is given in the picture below :
Rules
- Find the answer and then Comment in the comment section in this post.
- The contest is open for the entire STEEMIT community.
- Only one entry is allowed.
- Resteem this post(You can do it if you want, otherwise there is no problem )
- The prizes will be distributed if there is more than one correct answer.
5 Steem Prize Pool:
Rank | |
---|---|
1st | |
2nd | the rest will be distributed over every correct answer |
Post Submission Deadline
This contest will run for 4 Days(Comment before Bangladesh time 19-07-2021 , 11.59 pm (GMT+6)) and Then the result will be announced. So, participate soon.
Answer :- 1.21 A
@mashii-zen @patz99
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I = 0.833
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my entry
I = 0.833
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Total current of circuit = I = 0.83333
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I=3.96A
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My answer
I = 0.8333
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Hello @sandysparkle, Total current of the circuit I = 0.8333 Ampere
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I=0.8333
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l = 0.833
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Total current of the circuit I = 0.8333 Ampere
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Hi, @sandysparkle. This is my entry.
All images are my own. Edited in the PowerPoint program.
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I=1.21A
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My answer:
I=0.8333
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Hi @sandysparkle. I = 0.74A
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I=0.74A
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The answer is I=0.74A
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Ans : I=1.21A
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I=0.833A
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You are welcome
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my answer is
I = 1,6 A
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Buenas tardes la corriente total del circuito es igual a 1.21 Amperios
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My answer
I = 0.8333
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I=0.8333 Amperes
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The answer is I=0.74A
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Solving 20ohm, 30ohm and 40 ohm resisters. (as they are in series added simply)
R123= 90ohm
Solving R123 and 30ohm resister for parallel 1/R=> 1/90+ 1/30= 4/90
result: R=90/4
solving remaining two resisters and the resultant in series:
90/4+ 10+50= 330/4
I=V/R=> 400/330= 1.2121212121212121212121212121....
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