Hi @dwings, thank you for participating in the Industrial Electrical Homework. We have assessed your Homework post , and the below captures our assessments.

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A. You have determined the difference of the transformer by calculating the voltage and the turns of the primary and secondary coils. You haven't figured out the turns ratio of the transformer.

B. You have written the work nicely, identifying the different parts of a power transformer. However, it would be better if the marked parts of the transformer were more clear.

C. A step-down transformer is used for the electricity used in your house because the home appliances in our house are of low voltage. The transformer in the picture is an electronics transformer.

D. You have calculated a 6000 KVA transformer for a 5000 KW load, which is correct. You should know that 80% of the load of the transformer can be used in the load.

E. One mistake you made by looking at the nameplate of the transformer is that the low voltage will be 415 volts, not 415 KV. I hope you understand.

F. You have calculated the HT current of the transformer correctly. Your LT current output is not correct. You can match the LT current by looking at the name plate above.

G. Power factor is used by power companies for higher load users. Electricity companies bill penalties through power factor to prevent wastage of electricity by customers. Power factor improvement is done in the industrial sector by using power capacitors.

H. You mentioned the primary voltage of the transformer, but it would have been nicer to differentiate it by mentioning the secondary voltage. Your true/false judgment is correct.

Thank you for reading Industrial Electrical Lessons and doing homework. If the current rating of a transformer that is too large is wrong, it will cause a lot of damage. Hopefully you will learn to extract the current later. Good luck to you.