Boxes A, B and C contain 480 oranges altogether. 1/3 of the oranges in Box A were put into Box B. Then 1/5 of the Oranges in Box B were put into Box C. Finally, 1/6 of the oranges in Box C were put into Box A. There was an equal number of oranges in box at the end. How many oranges did each box contain at first.
Can You Solve?
7 years ago by ippo232 (59)
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We can solve this by working backwords.
At the end each box has 160 oranges so before we move 1/6 of the oranges from box C to box A there must be (128,160,192) oranges in the boxes A,B and C. So before we moved 1/5 of the oranges from box B to box C we must have had (128,200,152) oranges in the boxes. So before we moved 1/3 from A to B we must have had (192,136,152) oranges in each box which is the final answer
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Its very puzzle , I cant solve this
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This post has received a 0.10 % upvote from @speedvoter thanks to: @larryphang.
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