I want to win with Probability!!!

in mathematics •  7 years ago 

You are about to play a game with a coin that is weighted so that there is a 90% chance that it lands heads and a 10% chance that it lands tails. If you want to maximize the expected amount of money you will win, would you rather...

A. win $10 if it lands heads,

B. win $50 if it lands tails, or

C. win $1,000,000 if it spontaneously combusts in the air. (You may assume that there is at most a 0.0000001% chance that the coin will spontaneously combust in the air.)

Choose wisely!probab.png

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Assuming I win nothing when I lose a game the following will be my expected value of this discrete Bernoulli random variables
and assuming I only have one try.
for option A the E(x) = 0.910 + 00.1 = $9

for option c the E(x) = 500.1 + 00.9 = $5

for option C it is the chances of spontaneously combusts or not spontaneously combusts thus it it's Expected value is: 0.0000000011000000 + 99.9999...0 = $0,001

thus by pure expected value I would choose option A because it has the highest expected value. But lets say I can play any amount of games I want, then I will also choose option A for it has a stable and high chance of growth!.

so final answer overall, option A!