Merry Go Math

in mathematics •  8 years ago 

While watching my daughter twirl around on a merry-go-round (okay you got me, this picture is not my daughter), I was thinking about the implications of periodic functions. Obviously, if this merry-go-round continued spinning indefinitely at a constant speed, a basic periodic function would do the trick. But what about a more real world situation?



The merry-go-round slows down to a stop, stops for a short time, speeds back up and then does its spinning again. How would you write a function for that? And to make it even more complicated, sometimes the merry-go-round stops for longer or shorter intervals to allow for more or less kids to get on. I know a periodic function must repeat, but could you use an extra variable in there to represent the different lengths of times that it stops? Use some numbers if you like, but I would be very interested in your responses even with just variables to represent the different parts of this problem. Thanks in advance!
~ Curious math teacher here; read my introduction post! :)
https://steemit.com/introduceyourself/@melek/punish-a-white-kid-first-the-rule-i-didn-t-follow

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Of course you can!

Consider something like the following:

A_1(t)sin(w_1(t) t) + A_2(t)cos(w_2(t) t)

You allow A_1, A_2, w_1, and w_2 be functions of time, that will change amplitude and frequency.

Thanks! I'm playing around with it now. I'm grateful for people so much smarter than me taking the time to respond to my questions. I've read your posts and they are awesome. :)

This reminds me of some classical mechanics problems I encountered in college. Add a spring (like with Hooke's law) on a merry-go-round that is 10 meters from the center. Find the net force on the object after 5 seconds. Oh yeah, the merry-go-round has been pushed off a cliff and don't ignore wind resistance. All kidding aside, I always would start with a free-body diagram to try to my head around the problem. There must be some acceleration in the problem being that it is not going at a constant speed. At t=0, the velocity is zero. At t= whatever, it is at max velocity.

You just need to use
:p sorry, it's early here... upvoted

  ·  8 years ago Reveal Comment