RE: @steem-raffle drawing 73

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@steem-raffle drawing 73

in steem-raffle •  6 years ago 

The block in which the above post is included has a merkle root of d6c9df9884c4a590e2e891b99161946842aecd2e.
The last two digits of this root are used to determine if there is a winner. Ending in 0 gives an upvote and ending in 00 means the jackpot was cracked. The remaining digits determine which ticket wins. To do this we compute the residual after dividing the root by the number of virtual tickets. In this case this would be:
d6c9df9884c4a590e2e891b99161946842aecd = 4789945127657687545545064882727799579851534029 in base 10. The residual after dividing by the number of shares (821) is 346. Therefore ticket number 346 would win.

This time the root does not end in 0 and thus there is no winner in this drawing. The post will be upvoted to increase the jackpot

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