The following seems an easy question, to get the area of the rectangluar triangle with the slope equals to 10 and the height equals to 6.
据说是一个印度人杀入微软最后的面试, 面试官给了这么一道小学数学几何题:
If your answer is 30 (10×6/2), then you are falling into the trap: Such triangle doesn’t exist at all!
这哥门也有疑问 可是最后还是坚持 答案 30 (底 X 高 / 2)
不存在 It Doest Not Exist
这是个陷井: 这个直角三角形是不存在的. If we label the triangle with the following,
两个小直角三角形的勾股定理: What we can get are:
两者相加: If we add these two equations:
简化一下: After simplification, we have:
最后我们得到: Thus
因为
如果 并且 把函数 画出来是这样的
If and the function of is plotted below.
最大值是 25 也就是说 c 的最大值是 5 所以这样的三角形是不存在的(斜高是6)
The maximum value for function y is 25, which means that the maximum value of c is 5.
Such triangle does not exist (the height is 6, which exceeds the maximum length)!
这个问题的意义在于,在实际工作中,尤其是面对开放性,创造性的工作时,不能仅仅作为一个执行者,要怎么做,我也不知道
Typical Microsoft. If something is wrong then it is by design…and you are stuck with it.
Thank you for reading my post, feel free to FOLLOW and Upvote @justyy which motivates me to create more quality posts.
非常感谢阅读, 欢迎FOLLOW和Upvote @justyy 能激励我创作更多更好的内容。
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这个列的方程就可以了嘛。
不过这个面试换别的地方又出来另外一个版本
你答案如果是不存在这样的三角形 对不起 你 out
题目明确给出了数值,不需要你去质疑。你的任务就是完成公司给予的任务
哈哈
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嗯 你说得很对。
这题真是个坑。
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@jubi 貌似进过坑的样子
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We can place the longest side of a right triangle on the diameter of a circle, then the other 2 sides must meet at a point on the circumference.
This triangles longest aside is 10, the height cannot be longer than the radius of the circle, so not more than 5. Since this triangle's height is 6, it's area is 30, but it cannot be a right triangle.
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Thanks.. your explanation is excellent.
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Thank you!
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相比我們在銀行業工作的,你們的面試壓力真大。。
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10大互联网公司的面试题真的很难很难。。。。
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有意思
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对 O哥来说 肯定是小意思。
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It's too much intelligence for me
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Hi friend, very good !!!!!
You would help me with a vote in my post., Thanks !!! ;)
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确实是一道坑人的题。其实用长边为直径画一个半径是5的园就清楚了:高最多是5,也就是园的半径
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你的这种解法更快更好。
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Excellent analysis of this question - thanks
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You are welcome.
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Microsoft就是越来越难用,就是缺乏创新的表现。很好的观点哈
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微软已经慢慢的不是老大了
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I guess this problem can be interpreted in this way, also:
Denote the two endpoints of the line segment of length 10 by A and B. Now we wanna select a point P outside the line segment which makes the angle APB equal to the right angle. To satisfy this condition, P must lie on the circle of radius 5 centered at the midpoint of A and B. So we can immediately see that the maximum of the perpendicular distance from P to the line segment AB is 5.
Thank you for introducing a nice problem to think about :)
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Yes, this is more intuitive.
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答的那個該不該說先生你出錯題了..
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对的, 应该有敏锐的洞察力。
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put the right angle triangle into a round. The highest height of the triangle is the radius(5).把直接三角形放到圆里,最大高的也就是半径了,是5,不可能比5大。
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对的,就是这么简单。
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