Hi @us-andrew, thank you for participating in the Industrial Electrical Homework. We have assessed your Homework post , and the below captures our assessments.

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A. Judging the name by looking at the picture of the transformer is correct. The name of the transformer can be understood by looking at the turns of the primary and secondary coils. The turn ratio of the transformer is correct. Thanks for the nice presentation.

B. You have drawn a picture of a power transformer and described the working of various parts. It is very important to know the names and functions of the different parts of the transformer.

C. Your home transformer is a step-down transformer because electrical home appliances are of low voltage. Your answer is correct.

D. You have calculated a 6200 KVA transformer for a 5000 KW electrical load. You must remember that if the transformer is equal to the electrical load, you cannot use the full load. The transformer is used at 80% load. I hope you understand.

E. Identifying your transformer by looking at its nameplate is correct. It is a power transformer.

F. You have wrongly figured out the LT current. LT current of 2.5 KVA transformer shall be same as above nameplate. I hope you understand your mistake.

G. Power companies give power factor for consumers using higher loads. Power factor is used to prevent dissipation of real current. Power factor improvement is done in the industrial sector by using power capacitors or synchronous motors.

H. I have accepted your suggestion. After using the transformer, the writing on the nameplate gets erased day by day. The biggest difference in transformers is between primary and secondary voltage.

Thank you for reading Industrial Electrical Lessons and doing homework. It is very important to calculate the load of the transformer while building a product component company. I hope you will be successful in this task. Good luck to you.