Learn To Code : Simple Even and Odd program in C++

The simple Even and Odd program in C++ , i hope you will like this.

Integers which are perfectly divisible by 2 are called even numbers.

And those integers which are not perfectly divisible by 2 are not known as odd number.

To check whether an integer is even or odd, the remainder is calculated when it is divided by 2 using modulus operator %. If remainder is zero, that integer is even if not that integer is odd.

#include < iostream >
using namespace std;

int main( )

 {
int num;

cout << "Enter an integer":<<endl ;
cin >> num;

if ( num % 2 == 0)
    cout << num << " is even.";
else
    cout << num<< " is odd.";

return 0;

}

Enter an integer: 25
25 is odd.

Next time i enter :

Enter an integer:14
14 is even

In this program, if-else statement is used to check whether num%2 == 0 is true or not. If this expression is true, num is even if not num is odd.

Another Example for Even and Odd program.
you can also write program like this.

#include < iostream >
using namespace std;

int main()
{
int num;

cout << "Enter an integer: ";
cin >> num;

(num % 2 == 0) ? cout << num << " is even." : cout << num << " is odd.";

return 0;

}

Output :

Enter an integer: 27
27 is Odd

You can also use ternary operators ?: instead of if..else statement. Ternary operator is short hand notation of if-else statement.

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